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Angelina_Jolie [31]
3 years ago
6

Week 5 Test Taking skills, Page 2

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

20

Step-by-step explanation:

5/8 of 32

5/8×32=20

remember of means multiply

HOPE THIS HELP YOU HAVE A NICE DAY OR NIGHT

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8090 [49]
Do 45/225 and simplify and that’s your answer
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3 years ago
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What is the equation in point-slope form of a line perpendicular to y= ⅕ x+8, through the point (-2, 3) *
ivolga24 [154]

Answer:

it was right but ok

Step-by-step explanation:

First find the total number

6+4+5+3 = 18

6th graders : total

4 : 18

Divide each side by 2

4/2:   18/2

2 : 9

4 0
3 years ago
Help me please :>>>>>>>
Ket [755]

Answer:

C. Median

Step-by-step explanation:

If both sides are <em>symmetrical,</em> then there is no need to try and find the mean or anything because you already have the middle point and no outliers. <u>If there were outliers it'd be different</u>, unless the outliers were symmetrical with the rest of it, then the median would still be a good option.

5 0
2 years ago
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I don't know how to do this​
Gre4nikov [31]

Answer:

x = -11/5 and y = 24/5

Step-by-step explanation:

Use elimination.

First, we need to multiply so that at least one variable can cancel out.

We can multiply the top equation by 2.

So we get

4x + 6y = 20

Then, we can use elimination.

The x's cancel out.

So we get 5y = 24

Or y = 24/5

Then, we can plug in this y value back into the first equation to find x.

2x + 3(24/5) = 10

2x + 72/5 = 50/5

2x = -22/5

x = -11/5

So x = -11/5 and y = 24/5

5 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
2 years ago
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