3 years ago

Please help no links please!’n

Mathematics

1 answer:

denis-greek [22]3 years ago

4 0

Answer:

85.2

ggggggggggggggggggg

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How do you do question b?

notsponge [240]

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We use the result of part (a) and plug in (x,y) = (0,0). This is directly from the initial condition y(0) = 0.

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-----------------

This means,

$\arcsin(4y) = x^2 + C\\\\\arcsin(4y) = x^2 + 0\\\\\arcsin(4y) = x^2\\\\4y = \sin(x^2)\\\\y = \frac{1}{4}\sin(x^2)\\\\$

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