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Dimas [21]
2 years ago
8

Please help no links please!’n

Mathematics
1 answer:
denis-greek [22]2 years ago
4 0

Answer:

85.2

ggggggggggggggggggg

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Answer: B: It has a negative charge.

Step-by-step explanation:

According to theory espoused by the French physicist, Charles-Augustin de Coulomb, like charges charges will repel each other and unlike charges will attract one another.

This means that objects with negative charges will repel each other. As the first balloon in the question was negatively charged, it would only repel the other balloon if it was negatively charged as well.

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Can someone please explain this to me? Thanks!
Makovka662 [10]

Answer:  Choice D

\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\

==========================================================

Explanation:

Let g(t) be the antiderivative of g'(t) = \sqrt{1+t^3}. We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\

From here, we apply the derivative with respect to x to both sides. Note that the g(\pi) portion is a constant, so g'(\pi) = 0

\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\

\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\

Answer is choice D

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