Geometry help please

Mathematics

2 answers:

solmaris [256]3 years ago

6 0

Option 2 is the correct answer

Amanda [17]3 years ago

4 0

Q you can tell by moving this point 14 left and 3 down

You might be interested in

Given angle BEJ~RUW, what is RU?

harina [27]

RU is 34. To find the answer you can use a proportion. In this problem the proportion would be 60/51 = 40/x. You can then cross multiply giving you 51*40=60x. You can then solve for x which is your answer.

5 0

3 years ago

Please help me with the problems in my picture

Tamiku [17]

Answer:

1.) C

2.) miles

3.) Car A is faster

3 0

3 years ago

Expand & simplify: (x + 1)(x + 3)

Sindrei [870]

Answer:

368

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.