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kow [346]
3 years ago
14

It is known that a certain function is an inverse proportion. Find the formula for this function if it is known that the functio

n is equal to 12 when the independent variable is equal to 2.
Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

y=\frac{24}{x}

Step-by-step explanation:

We have been given that a certain function is an inverse proportion. We are asked to find the formula for the function if it is known that the function is equal to 12 when the independent variable is equal to 2.  

We know that two inversely proportional quantities are in form y=\frac{k}{x}, where y is inversely proportional to x and k is constant of variation.

Upon substituting y=12 and x=2 in above equation, we will get:

12=\frac{k}{2}

Let us solve for constant of variation.

12\cdot 2=\frac{k}{2}\cdot 2

24=k

Now, we will substitute k=12 in inversely proportion equation as:

y=\frac{24}{x}

Therefore, the formula for the given scenario would be y=\frac{24}{x}.

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Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas
zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048

Compute the probability of a person having a heart attack given that he or she has the disease:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0
3 years ago
Can someone answer this for me pls?
Aleks04 [339]

No. 1

x=2

y=0

Solve it by substitution method

Where,

y=2-x

and replace y at equation 1

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