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3 years ago

15

Ramona went to a theme park during spring break. She was there for 9 hours and rode 18 rides. At what rate did Ramona ride rides

in rides per hour?

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

2 rides per hour

Step-by-step explanation:

she rode 18 rides in 9 hours

therefore rate at which she rides = 18/9 = 2

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When both parties discuss the terms of a contract they are

marysya [2.9K]

B - Negotiating.

This is because they are communicating, they haven't yet agreed to anything or committed to the contract as neither parties have signed, thus leading to both C and D to be incorrect.

A, however, is not exactly a term used for this situation - contracting is more of a term used to say someone contracted a disease or the flu or etc.

Therefore, B would be correct as they are indeed negotiating the terms of the contract.

Hope this helps!

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4 years ago

Find the distance if mr.Nichols had been able to drive straight from the entrance to his campsite

Katyanochek1 [597]

hey! hope this helps

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4 years ago

Patty has 8 flowerpots, and she wants to plant a different type of flower in each pot. There are 11 types of flower available at

Dominik [7]

The combination formula is given by

C(n, r) = $\frac{n!}{(n-r)!r!}$

C(11, 8) = $\frac{11!}{(11-8)!8!}$

C(11, 8) = 165

So, there are 165 ways of choosing 8 flowers out of 11 flowers

7 0

4 years ago

The area of a circle is 28.26 square kilometers. What is the circles diameter

irinina [24]

Answer:

6km

Step-by-step explanation:

Area of circle = πr²

Where r = radius, π= 3.14, A = 28.26km²

A = 3.14 x r²

3.14 r2 = 28.26

Divide both sides by 3.14

r²= 28.26/3.14

r² = 9

Square root both sides

r= √9

r= 3

Radius = 3km

Note : Diameter = 2 x radius

Diameter = 3 x 2

Diameter = 6km

I hope this was helpful, Please mark as brainliest.

7 0

3 years ago

What is the determinant ? <br>ANS : -2 <br>plz help me with process

WITCHER [35]

Answer:

(-2)

Step-by-step explanation:

We have to find the determinant of the given matrix,

$A=\begin{bmatrix}(a-1) & (a^2-a+1)\\ (a+1) & (a^2+a+1)\end{bmatrix}$

det A = (a - 1)(a² + a + 1) - (a + 1)(a² - a + 1)

= a(a² + a + 1) - 1(a²+ a + 1) - a(a² - a + 1) - 1(a² - a + 1)

= a³ + a² + a - a² - a - 1 - a³ + a² - a - a² + a - 1

= (a³ - a³) + (-a² + a² - a² - a²) - 1 - 1

= -2

Therefore, determinant of the given matrix is (-2).

6 0

3 years ago