Answer:
So then the correct answer would be:
B) .9996
Step-by-step explanation:
The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and 
And we want this probability:
![P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation. [tex]np=600*0.4=240\geq 10](https://tex.z-dn.net/?f=%20P%28200%20%5Cleq%20X%20%5Cleq%20400%29%20%5Btex%5D%3C%2Fp%3E%3Cp%3EIn%20order%20to%20find%20this%20probability%20we%20can%20use%20the%20foloowing%20excel%20code%3A%3C%2Fp%3E%3Cp%3E%22%3DBINOM.DIST%28400%2C600%2C0.4%2CTRUE%29-BINOM.DIST%28199%2C600%2C0.4%2CTRUE%29%22%3C%2Fp%3E%3Cp%3EAnd%20we%20got%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%20P%28200%20%5Cleq%20X%20%5Cleq%20400%29%20%3D0.999675%5Btex%5D%3C%2Fp%3E%3Cp%3EBut%20for%20this%20case%20the%20problem%20says%20that%20we%20need%20to%20approximate%2C%20so%20then%20we%20can%20use%20the%20normal%20approximation%20to%20the%20normal%20distribution.%20%3C%2Fp%3E%3Cp%3EWe%20need%20to%20check%20the%20conditions%20in%20order%20to%20use%20the%20normal%20approximation.%0A%3C%2Fp%3E%3Cp%3E%5Btex%5Dnp%3D600%2A0.4%3D240%5Cgeq%2010)
So we see that we satisfy the conditions and then we can apply the approximation.
If we appply the approximation the new mean and standard deviation are:
And then 
And we are interested on the following probability:
So then the correct answer would be:
B) .9996
Answer:
$13.36
Step-by-step explanation:
12.5+6.25+3.8=22.55
35.91-22.55= 13.36
Ben has a longer ride because, .875 is bigger than .75
7/8=.875 3/4=.75
Yes it is possible for a line to only start in one quadrant and never leave that quadrant and vice versa a line can start in one quadrant and pass into another quadrant but how will you know if you line will be in certain or multiple quadrants simple just look at your points given if you have the points (3,4) (4,5) you notice that your X's are positive and your Y's are positive there is only one quadrant were your X and Y are positive and that is quadrant 1 but lets say you have points (-4,5),(3,4) you see how one of the points have a negative X and a positive Y there is only one quadrant that has a negative X and a positive Y that is quadrant 2 and and for point (3,4) that is in quadrant 1 so your line will run through quadrant 2 and 1
yes it is possible for a line to only be in one quadrant and it is also possible for a line to be in multiple quadrants basically it can be any place on a plane
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Answer:
Area of shaded : 21.5 cm^2
Step-by-step explanation:
Area of square = 10^2 = 100
Area of circle = 3.14 x 5^2 = 3.14 x 25 = 78.5
Area of shaded = 100 - 78.5 = 21.5 cm^2
