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3 years ago

Tom and Max are diving. Tom is 26 feet below sea level and Max is 8.25 feet above Tom. What is Max's elevation?

Mathematics

1 answer:

Vika [28.1K]3 years ago

5 0

Answer:

17.75 feet below sea level

Step-by-step explanation:

-26 + 8.25= -17.75

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A sphere has a radius of 7 millimeters. A second sphere has a radius of 4 millimeters. What is the difference of the volumes of

sattari [20]

The difference would be 371 1/3

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2 years ago

Plllsss help!!! <br>What is the value of x?

Flura [38]

Answer:

X = 149

Step-by-step explanation:

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360-211=149

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2 years ago

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|x − 5| − |2 − x| + |x + 1| , if x ≥ 5

son4ous [18]

Answer:

9990% 222$

Step-by-step explanation:

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2 years ago

Check whether the relation R on the set S = {1, 2, 3} is an equivalent

kozerog [31]

Answer:

$R$ isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let $S$ denote a set of elements. $S \times S$ would denote the set of all ordered pairs of elements of $S\!$ .

For example, with $S = \lbrace 1,\, 2,\, 3 \rbrace$ , $(3,\, 2)$ and $(2,\, 3)$ are both members of $S \times S$ . However, $(3,\, 2) \ne (2,\, 3)$ because the pairs are ordered.

A relation $R$ on $S\!$ is a subset of $S \times S$ . For any two elements $a,\, b \in S$ , $a \sim b$ if and only if the ordered pair $(a,\, b)$ is in $R\!$ .

A relation $R$ on set $S$ is an equivalence relation if it satisfies the following:

Reflexivity: for any $a \in S$ , the relation $R$ needs to ensure that $a \sim a$ (that is: $(a,\, a) \in R$ .)

Symmetry: for any $a,\, b \in S$ , $a \sim b$ if and only if $b \sim a$ . In other words, either both $(a,\, b)$ and $(b,\, a)$ are in $R$ , or neither is in $R\!$ .

Transitivity: for any $a,\, b,\, c \in S$ , if $a \sim b$ and $b \sim c$ , then $a \sim c$ . In other words, if $(a,\, b)$ and $(b,\, c)$ are both in $R$ , then $(a,\, c)$ also needs to be in $R\!$ .

The relation $R$ (on $S = \lbrace 1,\, 2,\, 3 \rbrace$ ) in this question is indeed reflexive. $(1,\, 1)$ , $(2,\, 2)$ , and $(3,\, 3)$ (one pair for each element of $S$ ) are all elements of $R\!$ .

$R$ isn't symmetric. $(2,\, 3) \in R$ but $(3,\, 2) \not \in R$ (the pairs in $\! R$ are all ordered.) In other words, $3$ isn't equivalent to $2$ under $R\!$ even though $2 \sim 3$ .

Neither is $R$ transitive. $(3,\, 1) \in R$ and $(1,\, 2) \in R$ . However, $(3,\, 2) \not \in R$ . In other words, under relation $R\!$ , $3 \sim 1$ and $1 \sim 2$ does not imply $3 \sim 2$ .

3 0

3 years ago

Solve for x. 4−(2x+4)=5 x=6 x=−52 x=−10 x=32

sashaice [31]

Answer:

Step-by-step explanation:

4−(2x+4)=5

4-2x - 4 =5

-2x = 5

x= -5/2 = -2.5

5 0

2 years ago