Determine the quadrant in which the terminal side of the given angle lies. -750°

Mathematics

1 answer:

Blababa [14]2 years ago

7 0

Answer:

Quadrant 4

Step-by-step explanation:

If the given angle was positive, then we go clockwise.

But it's negative so we go counterclockwise.

An alternative way of graphing

Quadrant 1 is 0-90°

Quadrant 2 is 90-180°

Quadrant 3 is 180-270°

Quadrant 4 is 270-360°

Subtract the given angle by 360 until no longer possible

750 - 360 = 390 390 - 360 = 30

Remember that this was originally a negative angle

Instead of going clockwise to quadrant 1, we go counterclockwise to quadrant 4, ending up at 330°

You might be interested in

How would you solve this problem.

Jet001 [13]

We can find h by calculating the area S of the parallelogram in two ways. We can write: $S=18\cdot10$ . On the other hand, $S=12\cdot h$ . Then:

$18\cdot10=12\cdot h\\\\ 12h=180\\\\h=\dfrac{180}{12}\\\\\boxed{h=15}$

7 0

2 years ago

Multiply 3xyz ^ 2 / 6y ^ 4 by 2y / x z ^ 4

Marat540 [252]

$\dfrac{3xyz^2}{6y^4}=\dfrac{3}{6}\cdot\dfrac{xyz^2}{y^4}=\dfrac{1}{2}\cdot\dfrac{xz}{y^3}=\dfrac{xz}{2y^3}\\\\\\\dfrac{3xyz^2}{6y^4}\cdot\dfrac{2y}{xz^4}=\dfrac{xz^2}{2y^3}\cdot\dfrac{2y}{xz^4}=\dfrac{2}{2}\cdot\dfrac{xyz^2}{xy^3z^4}=1\cdot\dfrac{1}{y^2z^2}=\dfrac{1}{y^2z^2}$