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kotegsom [21]
3 years ago
9

I need help answering these problems

Mathematics
1 answer:
IceJOKER [234]3 years ago
4 0

Answer:

6. \displaystyle \frac{33}{56} ≈ 0,5892857142... = tan\:B

5. \displaystyle \frac{56}{65} ≈ 0,8615384615... = cos\:B

4. \displaystyle \frac{33}{65} ≈ 0,5076923076... = sin\:B

3. \displaystyle 1\frac{23}{33} ≈ 1,696969... = tan\:A

2. \displaystyle \frac{33}{65} ≈ 0,5076923076... = cos\:A

1. \displaystyle \frac{56}{65} ≈ 0,8615384615... = sin\:A

Explanation:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

I am joyous to assist you anytime.

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ANSWER

g(x) =   {(x + 5)}^{3}  + 4

EXPLANATION

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x \to \:  {(x + 5)}^{3}  + 4

Or

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If f(x)=7x-7 what is f(8)+f(4)
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<u>Given Function is</u>

  • f ( x ) = 7x - 7 ------- eqn ( 1 )

<u>Now , put the value of x = 8 in eqn ( 1 )</u>

  • f ( 8 ) = 7 ( 8 ) - 7
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<u>Now , put the value of x = 4 in eqn ( 1 )</u>

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<h3 />

<u>From eqn ( 2 ) nd eqn ( 3 ) we get,</u>

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