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stira [4]
2 years ago
12

Identify the domain please thanks

Mathematics
1 answer:
Minchanka [31]2 years ago
3 0
Idk ask your teacher about that
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PLEASE HELP ME IS DUE TMR
IrinaVladis [17]

Answer:

p = 8000 + 2(6000)

20000

Step-by-step explanation:

Given that:

Profit in 1988 = 6000

Profit in 2003 = 8000 more Than double the profit made in 1998

Hence profit in 2003 (p) can be expressed as :

p = 8000 + 2(6000)

Hence profit in 2003

p = 8000 + 12000

p = 20,000

6 0
3 years ago
Describe how a point on a graph is related to a table and an equation that represent the same relationship.
castortr0y [4]

Answer:

because everything is relative to each other.

Step-by-step explanation: Graphing ordered pairs is only the beginning of the story. Once you know how to place points on a grid, you can use them to make sense of all kinds of mathematical relationships. A linear relationship is a relationship between variables such that when plotted on a coordinate plane, the points lie on a line. Let’s start by looking at a series of points in Quadrant I on the coordinate plane. Look at the five ordered pairs (and their x– and y-coordinates) below.

4 0
3 years ago
Read 2 more answers
25% of the students attended the school dance. if 32 attended the dance, how many students are there in all?
nadya68 [22]

Answer:

128 students in total

Step-by-step explanation:

25/100 = 1/4

1/4 = 32/ x

1 x 32

4 0
3 years ago
Options <br> A)117<br> B)39<br> C)3<br> D)63
hichkok12 [17]

Answer:

B. 39

Step-by-step explanation:

3x=117divided by 3=39

4 0
3 years ago
Simplify the problem: Sin theta Sec Theta
kherson [118]

Answer:

\tan \theta

Step-by-step explanation:

We have to simplify the following expression as given by

\sin \theta \times \sec \theta

= \frac{\sin \theta}{\cos \theta}

= \tan \theta ( Answer )

Because, we know that \sec \theta =\frac{1}{\cos \theta} and \tan \theta = \frac{\sin \theta}{\cos \theta}

If we consider \sin \theta = \frac{Perpendicular}{Hypotenuse} and \sec \theta = \frac{Hypotenuse}{Base},

then \sin \theta \times \sec \theta = \frac{Perpendicular}{Hypotenuse}\times \frac{Hypotenuse}{Base} = \frac{Perpendicular}{Base}= \tan \theta

3 0
2 years ago
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