Answer: Point of estimation = 32.60
Margin of error = 1.175.
95% confidence interval would be (81.95,84.45).
Step-by-step explanation:
Since we have given that
n = 49
Average = $32.60
Standard deviation = $5
We need to find:
1) Point of estimation for the mean of the population:
![\mu=\$32.60](https://tex.z-dn.net/?f=%5Cmu%3D%5C%2432.60)
2) At 90% level of confidence, z = 1.645
Margin of error would be
![z\dfrac{\sigma}{\sqrt{n}}\\\\=1.645\times \dfrac{5}{\sqrt{49}}\\\\=1.645\times \dfrac{5}{7}\\\\=1.175](https://tex.z-dn.net/?f=z%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5C%3D1.645%5Ctimes%20%5Cdfrac%7B5%7D%7B%5Csqrt%7B49%7D%7D%5C%5C%5C%5C%3D1.645%5Ctimes%20%5Cdfrac%7B5%7D%7B7%7D%5C%5C%5C%5C%3D1.175)
So, Margin of error = 1.175.
3) At 90% level of confidence, interval would be
![\bar{x}\pm 1.175\\\\=32.60\pm 1.175\\\\=(32.60-1.175,32.60+1.175)\\\\=(31.425,33.775)\\\\=(31.43,33.76)](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%5Cpm%201.175%5C%5C%5C%5C%3D32.60%5Cpm%201.175%5C%5C%5C%5C%3D%2832.60-1.175%2C32.60%2B1.175%29%5C%5C%5C%5C%3D%2831.425%2C33.775%29%5C%5C%5C%5C%3D%2831.43%2C33.76%29)
Hence, 90% confidence interval would be (31.43,33.76).
Answer:
BC and AD mean the same thing as BCE and CE. Image via Artoba Tours.
(a) 4, ·b)
, (c)
, (d)
using the slope m of a line = tanΘ = (difference in vertical )/(difference in horizontal ) between 2 points on the line
using the endpoints of each line, then
(a) tan Θ =
= 4
(b) tan Θ = ![\frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D)
(c) tan Θ =
= ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
(d) tan Θ = ![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
You can solve this with proportion
1) For 2h
9/2 mile : 3/4h = x mile : 2h => (3/4)x=(9/2)*2 => (3/4)x=9 => x=9*(4/3)= 12miles
For 3h => (3/4)x=(9/2)*3 When we divide equation with 3 we get
x/4=9/2 => x=(9/2)*4=18 miles
2) 2 combine : 320 acres = 7 combines : x acres +: 2x= 320*7 =>
x= (320*7)/2 = 160 * 7 = 1120 acres
Good luck!!!