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Iteru [2.4K]
3 years ago
10

Please help simplify the expression

Mathematics
2 answers:
hjlf3 years ago
7 0

Answer:

6+3v

Step-by-step explanation:

(2+v) *3

Distribute

2*3 + v*3

6+3v

bazaltina [42]3 years ago
3 0
6+3v is the correct answer
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What is the range of tan x?<br><br> 1) all real numbers<br> 2) -1<br> 3) y&gt;0
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all real Numbers may be

4 0
3 years ago
f (x), has (x-7) and (x+4i) as factors. F(X)=2x^5-13x^4+22x^3-187x^2-160x+336 what is the total number of real numbers of real z
Murljashka [212]

Answer: 3

<u>Step-by-step explanation:</u>

(x + 4i) is a root which means its conjugate (x - 4i) is also a root

(x + 4i)(x - 4i) = x² + 16


Use Long Division for 2x⁵ - 13x⁴ + 22x³ - 187x² - 160x + 336 ÷ x² + 16

           <u> 2x³ - 13x² - 10x + 21                             </u>  

x² + 16 ) 2x⁵ - 13x⁴ + 22x³ - 187x² - 160x + 336

           - <u>(2x⁵ + 0x⁴ + 32x³) </u>   ↓          ↓         ↓

                       -13x⁴ - 10x³ - 187x²     ↓         ↓

                    - <u>(-13x⁴ +0x³ - 208x²)  </u>  ↓         ↓

                                  -10x³ + 21x² - 160x     ↓

                               - <u>(-10x³  + 0x² - 160x)</u>    ↓

                                               21x² + 0x + 336

                                            - <u>(21x² + 0x + 336)</u>

                                                                      0


Use Synthetic Division to divide (x - 7) by the reduced polynomial (2x³ - 13x² - 10x + 21)

7 |  2   -13   -10   21

  <u>|  ↓    14     7   -21  </u>      

    2      1     -3     0  ← remainder is 0      


Use grouping to factor the reduced polynomial (2x² + x - 3)  

 2x² - 2x + 3x - 3

= 2x(x - 1) +1(x - 1)

= (2x + 1)(x - 1)  


The factors are: (x - 7) (2x + 1) (x - 1) (x + 4i) (x - 4i)

The first 3 are real roots and the last 2 are complex roots

3 0
3 years ago
Shane covered the front of the kite with paper. How many square inches of paper did shane use? 14 in
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Answer:

84 square inches

Step-by-step explanation:

7 0
4 years ago
Please someone help me to prove this. ​
kvv77 [185]

Step-by-step explanation:

This is known as the triple cotangent identity, and it is only valid if the three angles add up to π/2.

A/2 + B/2 + C/2 = π/2

Let's define the complement of each angle:

α = π/2 − A/2

β = π/2 − B/2

γ = π/2 − C/2

Add the complements together:

α + β + γ

= (π/2 − A/2) + (π/2 − B/2) + (π/2 − C/2)

= 3π/2 − (A/2 + B/2 + C/2)

= 3π/2 − π/2

= π

Therefore, the triple tangent identity applies.

tan α tan β tan γ = tan α + tan β + tan γ

Substitute:

tan(π/2 − A/2) tan(π/2 − B/2) tan(π/2 − C/2) = tan(π/2 − A/2) + tan(π/2 − B/2) + tan(π/2 − C/2)

Use reflection identity:

cot(A/2) cot(B/2) cot(C/2) = cot(A/2) + cot(B/2) + cot(C/2)

6 0
3 years ago
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