Solve the following equation: 6.4x + 8.2 = 85

Mathematics

1 answer:

Svetllana [295]3 years ago

8 0

Answer:

X=12

if you are happy with my answer, please give brainliest :)

Step-by-step explanation:

Subtract 8.2 from both sides

76.8=6.4x

x=12

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Perform the indicated operation. (4g 2 - 9) ÷ (2g - 3) 2g - 3 2g + 3 2g + 3 R 18

Sveta_85 [38]

(4g^2 - 9) --> this can be factored out.
After factorization, you will get --> (2g-3)(2g+3)

Divide the whole factor by (2g-3)
[ (2g-3)(2g+3) ] / (2g-3)
The final answer is 2g + 3.

5 0

4 years ago

Read 2 more answers

I need help please!!!!

givi [52]

Answer:

1/3( x-5)= -2/3

Multiply both sides by 3

x = 3

Step-by-step explanation:

1/3( x-5)= -2/3

Multiply both sides by 3

3*1/3( x-5)= -2/3*3

x-5 = -2

Add 5 to each side

x-5+5 = -2+5

x = 3

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3 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$