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Minchanka [31]
2 years ago
9

Evaluate the following using the distributive property 6(3+9)

Mathematics
2 answers:
Nikolay [14]2 years ago
7 0
18+54 is the answer lol
Marrrta [24]2 years ago
5 0

Answer:72

Step-by-step explanation:

First you would multiply 6 with 3 and 9 because you would distribute. You would get 18+54 then you would add to get 72.

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Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Helpp please ! need to<br> show work for geometry
podryga [215]

Answer:

45 degrees

Step-by-step explanation:

AOB = 140°

and an the angle bisector(OC) is a line which will divide AOB into 2 equal angles

which is 140÷2= 70

and if AOD = 25 then COD= 70-25

= 45 degrees

hope it helps

3 0
2 years ago
Solve for x <br> -3x+8y= 5 <br> 6x - 2y=10<br><br> x= 15/7<br> x=10/7<br> x=5/7<br> x=5/2
oee [108]
I got 10/7 hope helped u
3 0
3 years ago
Eric has 4 pieces of clay he cut out each piece of clay into thirds how many 1/3 size pieces of clay does Eric have
Ivahew [28]

Answer:

ERIC HAD 12 PIECES OF CLAY LEFT

Step-by-step explanation:

1/3 + 4 = 12

4 0
3 years ago
Need help with all questions.
agasfer [191]
Im in your class at school im kayla
8 0
3 years ago
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