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3 years ago

Explain relationship between how radical expressions and rational (fractional) exponents

Mathematics

1 answer:

RideAnS [48]3 years ago

3 0

Answer:

Any radical in the form can be written using a fractional exponent in the form . The relationship between and works for rational exponents that have a numerator of 1 as well. For example, the radical can also be written as , since any number remains the same value if it is raised to the first power.

Step-by-step explanation:

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3 years ago

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Answer:

easy:

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What is the solution, if any, to the inequality 10x1207

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Answer:

i think option b

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Step-by-step explanation:

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2 years ago

Consider a candle that has a volume of 96 cubic inches and a weight of 44.16 ounces. What is the density of the candle? The dens

Ahat [919]

Answer:

1. 55.271 inches/lb

2. 3.075 inches/lb

3. The denser one is the pine, so it would be heavier.

Step-by-step explanation:

1. density of the pine log (which is a cylinder)

We need the weight/mass and the volume.

V(cylinder) = πr^2 * height

= πr^2 = π(5^2) = 25π = 78.54

= 78.54 * 30 = 2356 cubic inches

The weight is 42.63.

Density = mass/volume = 2356/42.63 = 55.271 inches/lb

2. density of the oak board (which is a rectangular prism)

We need the weight/mass and the volume.

V(prism) = l*w*h

= 5.5*1.5*3 = 24.75 cubic inches

The weight is 8.05.

Density = mass/volume = 24.75/8.05 = 3.075 inches/lb

3. Picture a box made out of stone and a box made out of cardboard. Same dimensions, but the stone one would be way heavier because stone is denser.

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3 years ago

The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB)=10log[1/10], where I &a

Alexandra [31]

For this case we have the following equation:
$I(dB)= 10log(\frac{I}{I0})$
Where,
I: the intensity of a given sound
I0: the threshold of a hearing intensity
Substituting values in the given equation we have:
 $I(dB)= 10log(\frac{10^8I0}{I0})$
Rewriting the equation we have:
 $I(dB)= 10log(10^8)$
Then, by properties of logarithm we have:
 $I(dB)= 10(8)$
Finally we have:
 $I(dB)=80$
Answer:
The intensity, in decibles, [I(dB)], when I=10^8(I0) is:
D.80

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4 years ago

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