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ololo11 [35]
3 years ago
13

Determine the percent of change From 45 ft to 92 ft

Mathematics
1 answer:
malfutka [58]3 years ago
3 0

Answer:

104.44%

Step-by-step explanation:

You might be interested in
Simplify the expression
makvit [3.9K]

Answer:

3x+18

Step-by-step explanation:

6+3(x+4)=6+3x+12

              =3x+18

7 0
3 years ago
Can someone please answer this I don’t understand!
Dovator [93]

The coordinates of X are (5, 11).

Solution:

Given points of the line segment are P(2, 2) and T(7, 17)  

Let X be the point that partitions the directed line segment PT in the ratio 3 : 2

Using section formula, we can find the coordinate of the point that partitions the line segment.

Section formula:

$X(x, y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=2, y_{1}=2, x_{2}=7, y_{2}=17 and m = 3, n =2

Substitute these in the section formula,

$X(x, y)=\left(\frac{3 \times 7+2 \times 2}{3+2}, \frac{3 \times 17+2 \times 2}{3+2}\right)

            $=\left(\frac{21+4}{5}, \frac{51+4}{5}\right)

           $=\left(\frac{25}{5}, \frac{55}{5}\right)

           =(5, 11)

X(x, y) = (5, 11)

The coordinates of X are (5, 11).

6 0
3 years ago
An english book is comprised of two sections, literature and grammar, in a ratio of 3:2. How much of each type of content will b
Finger [1]

Since your total for the English book is 5, you make a ratio of

5:150

to make 5 equal 150, you multiply by 30. So if you multiply 3 by 30, you get 90, and 2 by 30 you get 60

60+90=150

new ratio-  90:60

or 90 pages of literature and 60 pages of grammar

7 0
3 years ago
y=c1e^x+c2e^−x is a two-parameter family of solutions of the second order differential equation y′′−y=0. Find a solution of the
vagabundo [1.1K]

The general form of a solution of the differential equation is already provided for us:

y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},

where c_1, c_2 \in \mathbb{R}. We now want to find a solution y such that y(-1)=3 and y'(-1)=-3. Therefore, all we need to do is find the constants c_1 and c_2 that satisfy the initial conditions. For the first condition, we have:y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.

For the second condition, we need to find the derivative y' first. In this case, we have:

y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.

Therefore:

y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.

This means that we must solve the following system of equations:

\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.

If we add the equations above, we get:

\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e}  \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.

If we now substitute c_1 = 0 into either of the equations in the system, we get:

c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}

This means that the solution obeying the initial conditions is:

\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.

Indeed, we can see that:

y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3

y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,

which do correspond to the desired initial conditions.

3 0
3 years ago
You buy a patty for $200 and pay 16% in tax (G.C.T). How much is money was paid to the cashier?
AleksAgata [21]

Answer:

$232

Step-by-step explanation:

Add 16% to 100% then multiply by 200

6 0
3 years ago
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