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kondaur [170]
3 years ago
14

Suppose an object is dropped from a height h0 above the ground. Then its height after t seconds is given by h = −16t 2 + h0, whe

re h is measured in feet. Use this information to solve the problem.
A ball is dropped from the top of a building 59 ft tall. (Round your answers to three decimal places.)
(a) How long will it take to fall half the distance to ground level?
t = sec
(b) How long will it take to fall to ground level?
t = sec
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
3 0

Answer:

Step-by-step explanation:

Given

h=-16t^2+h_0

ball is dropped from a height of 59 ft

therefore h_0=59 ft

h=-16t^2+59

Time taken to fall half the distance to the ground level i.e. h=\frac{59}{2}

\frac{59}{2}=-16t^2+59

arranging we get

16t^2=\frac{59}{2}

t^2=\frac{59}{2\times 16}

t=1.35 s

(b)Time taken to fall

i.e. h=0

0=-16t^2+59

16t^2=59

t^2=\frac{59}{16}

t=1.92 s

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