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3 years ago

Solve and SHOW YOUR WORK for the equation 3(4x – 2) = 9 + 2x + 5

Mathematics

2 answers:

Rufina [12.5K]3 years ago

6 0

I wrote how to do it on paper and uploaded the files. Hope this helps. :D

enot [183]3 years ago

3 0

Remember
you can do anyting to an equaiton as long as you do it to both sidess

distributive property
a(b+c)=ab+ac
commutativ property
a+b=b+a

distribute
3(4x-2)=12x-6

12x-6=9+2x+5
add 6 both sides
12x+6-6=9+6+5+2x
12x+0=20+2x
minus 2x
10x=20
divide 10
x=2

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The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

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Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

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switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

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$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

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$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

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