Math please help me please help me please help me

F(3)=-3, f(2)=2 find the linear function

crimeas [40]

.....................

8 0

3 years ago

Zane received a quote to move his belongings to his new house. The estimate from

erik [133]

9514 1404 393

Answer:

packing: $50 per hour
loading: $75 per hour
packing LCM: 12; loading LCM: 15

Step-by-step explanation:

We can let P and L represent the hourly costs of packing and loading, respectively. The two estimates can be represented by the equations ...

6P +5L = 675

4P +3L = 425

The LCM of the coefficients of P is LCM(6, 4) = 12.

The LCM of the coefficients of L is LCM(5, 3) = 15.

__

Each LCM is the product of the numbers, divided by their greatest common factor. For 4 and 6, the product is 24, and both even numbers have a factor of 2, so the LCM of 4 and 6 is 24/2 = 12. The numbers 3 and 5 have no common factors, so the LCM is simply their product.

_____

The LCM is useful if you're going to solve the equations by "elimination". Here, the LCM of 12 means we can eliminate P by making its coefficient be 12 in both equations. Multiplying the first equation by 2, we can subtract 3 times the second equation to eliminate P:

2(6P +5L) -3(4P +3L) = 2(675) -3(425)

12P +10L -12P -9L = 1350 -1275

L = 75 . . . . . simplify

Similarly, we can eliminate L by making its coefficients be 15.

5(4P +3L) -3(6P +5L) = 5(425) -3(675)

20P +15L -18P -15L = 2125 -2025

2P = 100 . . . . simplify

P = 50 . . . . . . divide by 2

The hourly rates are ...

$50 per hour for packing

$75 per hour for loading

7 0

3 years ago

Read 2 more answers

When is a concurring opinion written?

Fiesta28 [93]

Answer: A) when a supreme court justice agrees with the majority decision

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

What is 86 as a fraction in simplest form

Gwar [14]

The answer would be 46/50

5 0

3 years ago

1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago

Math please help me please help me please help me​

Math please help me please help me please help me