answer:
-1/2
explanation in case you don't understand:
so, let's look at the original equation.
-1 1/6 divided by 2 1/3.
to read it easier, add parenthesis to the fractions.
(1 1/6) / 2 1/3.
That equals 0.5. Now we have to turn it to a fraction.
O.5 is one half of a whole, so 0.5 would equal to 1/2.
always happy to help! :)
Answer:
150
Step-by-step explanation:
A sample of metal has a mass of 3,600 grams. The sample is in the
shape of a rectangular prism that has dimensions of 2 centimeters by
3 centimeters by 4 centimeters. What is the density of the sample?
so you would times 3*4*2=24 then you would do 3,600/24=150
A. 32/4=8
B. Square root of 9 = 3
Answer:
S(x) = 360 + 0.025x
Step-by-step explanation:
Let Sm be Salary per month
Let x be sales per month
Let S(x) be savings per month
Sm = 1800 + 0.1x
where 0.1x is the commission on sales
S(x) = 20% of 1800 + 25% of 0.1x
20% of 1800 = 20/100 * 1800 = 360
25% of 0.1x = 25/100 * 0.1x = 0.025x
Therefore,
S(x) = 360 + 0.025x
Answer:
After 2 minutes the temperature of the hot chocolate will be 149.46 degrees Fahrenheit.
Step-by-step explanation:
We are going to use the Newton's law of cooling to solve this exercise. The Newton's law of cooling states that the amount of heat lost by a body is proportional to the difference of temperature between the body and the enviroment. We are going to use the following function :
T(t)=T_{0}+(T_{i}-T_{0}).e^{-kt}T(t)=T
0
+(T
i
−T
0
).e
−kt
Where ''T(t)'' is the temperature of the body that depends of the variable ''t'' which is time.
Where T_{0}T
0
is the temperature of the surroundings
In this case T_{0}T
0
is the temperature of the freezer
Where T_{i}T
i
is the initial temperature of the body which is cooling. In this case, T_{i}T
i
is the temperature of the hot chocolate
And where ''k'' is a constant. In this case, k=0.12k=0.12 is a data of the exercise
If we replace all the values in the equation and replacing t=2minutest=2minutes
⇒
T(2minutes)=0+(190-0).e^{-(0.12).(2)}T(2minutes)=0+(190−0).e
−(0.12).(2)
T(2minutes)=(190).(e^{-0.24})=149.46T(2minutes)=(190).(e
−0.24
)=149.46
We find that the temperature of the hot chocolate after 2 minutes is 149.46 degrees Fahrenheit
