According to the given question we have the following equations:
a. x2+3x-3=0
b. 3x2-7x=12
a. X2+3x-3=0
The first step to calculate this equation is:
Move the -3 to the other side:
So, the equation would be:
X2+3x=3
x2+3x=5x
Therefore:
5x=3
x=3/5
a. The value of x would be 3/5
b. 3x2-7x=12
First step:
Multyply 3x to 2, so:
3x*2=6x
Next we can proceed to calculate the value of x:
6x-7x=12
-x=12
x=-12
b. The value of x would be -12
<span>False....................................................</span>
4x−5=7+4y
subtract 7 from both side
4x - 5 -7 = 4y
4x -12 = 4y
divide by 4
4x/4 -12/4 = 4y/4
x-3=y
Answer:



.
Step-by-step explanation:
We use the Venn diagram to calculate the desired probabilities.
Note that there are 6 possible results in the sample space
S = {1, 2, 3, 4, 5, 6}
Then note that in the region representing the intercept of A and B there are two possible values.
So

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}
So

In the region that represents event B there are 3 possible outcomes {1, 2, 6}
So
.
Now


<em>Hey</em><em>!</em><em>!</em>
<em>1</em><em> </em><em>and </em><em>2</em><em> </em><em>are</em><em> </em><em>vertical</em><em> </em><em>angles</em><em>.</em>
<em>Vertically</em><em> </em><em>opp</em><em>osite</em><em> </em><em>angles</em><em> </em><em>are</em><em> </em><em>always</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>each</em><em> </em><em>other</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em>