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Andreas93 [3]
3 years ago
9

X^2 - 2x - 63 = 0

Mathematics
1 answer:
MAVERICK [17]3 years ago
7 0

Step-by-step explanation: When an equation has a squared term in it

such as x² - 2x - 63 = 0, it's called a polynomial equation.

The rule for solving a polynomial equation is

to first set it equal to 0, them factor.

Since this equation is already set equal to 0, we can factor the left side.

To factor x² - 2x - 63, look for factors of -63 that add to -2.

In this case, these factors are -9 and +7.

So we have (x - 9)(x + 7) = 0.

When two terms are multiplying together to equal 0,

either one term or the other must equal 0.

So x - 9 = 0 or x + 7 = 0.

Solving for x in each equation, we get x = 9 or x = -7.

So this equation has two solutions and we write out answer

in set notation which looks like this {9, -7}.

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Enter your answer and show all the steps that you use to solve this problem in the space provided.
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Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

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ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

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(c). Subtract terms with the same exponent of x

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ƒ(x) -g(x) =      4x³ + 2x² + 2x

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