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ZanzabumX [31]
3 years ago
12

2. Janet baby-sat for 28 hours over two weeks. She earned $5.00 an hour. What was her gross pay?

Mathematics
2 answers:
BaLLatris [955]3 years ago
8 0

Answer:

$140

Step-by-step explanation:

Nata [24]3 years ago
7 0

Answer:

$140.00

Step-by-step explanation:

Gross pay is the pay before any deductions by taxes or other reason.

Simply multiply the five dollars by twenty-eight hours.

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Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan
Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

So

P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917

0.3917 = 39.17% probability that she had found someone to help

4 0
3 years ago
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3 years ago
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The answer is B.) 3

I hope this helped!
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7. \frac{1}{127}

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