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VladimirAG [237]

2 years ago

9

On Friday,1/6 of band practice was spent trying on uniforms.The band spent 1/4 of practice on marching.The remaining practice ti

me was spent playing music.What fraction of practice time was spent playing mussic?

1 answer:

Salsk061 [2.6K]2 years ago

7 0

I mean I got 5/12 as my simplified answer but I might be wrong. I hope this helps in some way and sorry if I'm wrong

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Solve In (2x+3)=7 round to the nearest thousandth

e-lub [12.9K]

To solve this problem you must apply the proccedure shown below:

1. You have:
<span>
In(2x+3)=7

2. Then, you must apply log(e), as below:
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In(2x+3)=ln(e^7)

3. Now, you obtain:

2x+3=e^7

4. Youy must clear the variable "x", as below:

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2 years ago

Which of the following proportions can be used to find the value of n?

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The variable y varies directly with the variable x.

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What percentage of the semi circle is shaded? <br>

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$

$r \approx 23.606\,\%$

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

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2 years ago