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ASHA 777 [7]
3 years ago
7

3xyz is also a choice but once again i can’t simplify

Mathematics
1 answer:
Nataliya [291]3 years ago
5 0

Answer:

3xyzsquare root of xy^2

the third option

Step-by-step explanation:

look for what you cn take from all of it equally

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PLEASE ANSWER ASASP<br> -5y + 4 = -11<br> what is y?
lorasvet [3.4K]

Answer:

3

Step-by-step explanation:

-5y + 4 = -11   Get rid of the numbers to get y alone.

-5y +4 minus 4 = -11 minus 4    Here you are removing the 4 from the left

-5y = -15       Now you will have to get rid of the -5

-5y/(-5) = -15/(-5)    

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2 years ago
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Give a example of two fractions with the quotient of 5/12
olasank [31]
Poorly phrased question, but the general answer is 5k/(12k), where k <span>∈ Z (i.e. k is an integer).

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3 years ago
The product of a number t and 6 increased by 1 is equal to 43
Flura [38]
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2 years ago
Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

6 0
2 years ago
An experiment consists of drawing 1 card from a standard​ 52-card deck. let e be the event that card drawn is a 33. find​ p(e).
Dafna1 [17]

1 out of 52. So 1/52 equals some decimal. Plug in calc.

4 0
3 years ago
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