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3 years ago

10

Angle ABC measures 90 degrees. It has been split into two angles angle ABD and angle DBC. The measure of the two angles is in a

ratio of 2:1. What are the measures for each angle.

1 answer:

9966 [12]3 years ago

8 0

Answer:

the angle measures are 60 and 30

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project is graded on a scale of 1 to 5. If the random variable, X, is the project grade, what is the mean of the probability dis

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The set given by the project grade is {1, 2, 3, 4, 5}. If the random variable, X, is the project grade, the mean of the probability distribution is determined by:

Sum = 1 + 2 + 3 + 4 +5
= 15
Mean of the probability distribution is 15/n, where n = 5
= 15/ 5
= 3

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Can someone help me with this

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Answer:

Step-by-step explanation:

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

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Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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3 years ago

Sylvia is changing the light bulbs of the big light fixture in her dining room. She finished 1 5 of the bulbs in 10 minutes. Wha

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Answer:

D

Step-by-step explanation:

5/5 -1/5=4/5

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What are the measurements?

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