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Gnesinka [82]
3 years ago
13

Write a conditional statement that correctly describes each venn diagram in the space provided?

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0
Remember that a conditional statement (p→q) is an if-then in which the first part, p, is the hypothesis and the second part, q, is the conclusion. 

1. Here the set m<span>∠A=40° is a subset of the set Acute Angles, so </span>m∠A=40° is the hypothesis and Acute Angles is the conclusion. 
In other words:
m∠A=40°→∠A is an Acute Angle 
if m∠A=40°, then ∠A is an Acute Angle

We can conclude that the conditional statement that describes the Venn diagram is: if m∠A=40°, then ∠A is an Acute Angle

2. Just like before, the set 2x=4 is a subset of the set x=2; therefore, 2x=4 is the hypothesis and x=2 is the conclusion.
In other words:
2x=4→x=2
if 2x=4, then x=2

We can conclude that the conditional statement that describes the Venn diagram is: if 2x=4, then x=2
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Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9
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Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that \mu = 20.5, \sigma = 0.9

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.5}{0.9}

Z = 0.56

Z = 0.56 has a p-value of 0.7123

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 20.5}{0.9}

Z = -1.67

Z = -1.67 has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

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