12,,389+15
I’m not for sure but used photomath
The answer is 24 because you have to do 6x4=24
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that:
v = v0 - a · t1
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
Answer:
1.49714285714
Step-by-step explanation:
6/7+4/5*4/5
=6/7+0.64
=1.49714285714
Answer:
34.10
Step-by-step explanation:
Note:
16% = .16
Important:
What was the <u>old price</u> of the shoes
Solution:
40.60 x .16 = 6.946 [Round:6.50]
40.60-6.50= 34.10
Hence, the old price of the shoes is $34.10
