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ddd [48]
3 years ago
15

What is f(4) – g(3)?

Mathematics
1 answer:
const2013 [10]3 years ago
7 0

Answer:

f4-g3

Step-by-step explanation:

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What is the linear inequalitie of m=2 over 7
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Answer:

Step-by-step explanation:

m=2ov(2.718282)r(7)

Answer:

m=38.055946orv

I think hope this is correct

5 0
3 years ago
Mary has sold 90 boxes of cookies. If her goal was to sell 120 boxes, what percentage of her goal has she sold?
Westkost [7]

the percentage is 75%

because 90 divided by 120 is 0.75.

6 0
3 years ago
Mark is mixing different color paints for a mural
anygoal [31]

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25r+22b+65s

Step-by-step explanation:

ok so like uhh yea

7 0
3 years ago
What is 600 is 10 times as much as
svetoff [14.1K]

Let x = our unknown number

10x = 600

Divide by 10 on both sides to isolate the variable x.

x = 600/10

x = 60

600 is 10 times as much as 60.

8 0
4 years ago
Will crown the correct answers brainliest 3x
Solnce55 [7]

Answer :

(1) \frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}

(2) \frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}

(3) \frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}

(4) \frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}

(5) \frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}

(6) \frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}

Step-by-step explanation :

(1) The given expression is: \frac{1}{x}+\frac{1}{y}

\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}

(2) The given expression is: \frac{1}{5x}+\frac{1}{3y}

\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}

(3) The given expression is: \frac{1}{7x}-\frac{1}{2y}

\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}

(4) The given expression is: \frac{2}{5x}+\frac{3}{7y}

\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}

(5) The given expression is: \frac{7}{11x}-\frac{1}{33y}

\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}

(6) The given expression is: \frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}

\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}

7 0
3 years ago
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