Ask question

Ask question

All categories

3 years ago

6

calculate the surface of each 3D shape below then from the right, drag and drop the correct surface area calculation into the bo

x below with the corresponding shape

1 answer:

Vikentia [17]3 years ago

6 0

Answer:

thy

Step-by-step explanation:

You might be interested in

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

Tanyss's house has 25 windows. Her brother has washed 22 of the windows. What percent of the windows has her brother washed?

AveGali [126]

Answer:

88

Step-by-step explanation:

7 0

3 years ago

HELP MEE PLEASE HELP

SOVA2 [1]

Answer:

42.75

Step-by-step explanation:

area of one piece, length x width: 3 x 4 3/4

14.25

area of 3 pieces: 14.25(3)= 42.75

8 0

2 years ago

Ask me by rounding each mixed number to the nearest whole number 11/18+6 1/10

Agata [3.3K]

The answer is below what the dude said

4 0

3 years ago

Let angle G be an acute angle and tan G = 0.43 . Use technology to approximate the measure of angle G to the nearest 10th of a d

klasskru [66]

We need to use the calculator, using the tan⁻¹ function:

$\begin{gathered} \tan(G)=0.43 \\ \tan^{-1}(\tan(G))=\tan^{-1}(0.43) \\ G=\tan^{-1}(0.43) \end{gathered}$

Using the calculator:

$G=\tan^{-1}(0.43)=23.26770481$

To the nearest tenth:

$G=23.3º$

6 0

1 year ago