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fomenos
2 years ago
8

Select all the expressions that are equivalent to -90x+60.

Mathematics
1 answer:
Ber [7]2 years ago
7 0

Answer:A, B and C

Step-by-step explanation:

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Can somebody fill in the blanks for me.
alukav5142 [94]

Answer:

Step-by-step explanation:

2: exterior and opposite

3:supplementary

5: angles and equal

6: supplementary

4 0
3 years ago
I need 6x-8=5x+4 solved
Julli [10]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

6x-8=5x+4  Equation/Question

Step 2

6x-8=5x+4  simplify

6x-8=5x+4

Step 3

6x-8=5x+4  Subtract

x-8=4

Step 4

x-8=4  Add 8

answer

x=12

Hope this helps

8 0
2 years ago
Read 2 more answers
I need to know the equation for this table!
Kobotan [32]

The equation for the table is y=2x+3.

7 0
3 years ago
A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro
Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let \mu be the true mean weight per apple the company ship.  We want to test the next hypothesis

H_{0}:\mu=120 vs H_{1}:\mu\neq 120 (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}} which is normally distributed. The observed value is  

z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583. The rejection region for \alpha = 0.05 is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0
3 years ago
3x+2y=6 and y=1/3x-11 perpendicular or parallel
IgorLugansk [536]

Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.

For two lines  y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate  k1 and k2.

To calculate the slope k of any line, you have to change the equation to y=kx+b

For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))

For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)

Now you can get the answer: The two lines neither parallel nor perpendicular.

6 0
2 years ago
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