2 years ago

Pls help!!!!!!!!!!!!!!

Mathematics

1 answer:

Lady_Fox [76]2 years ago

4 0

Answer:

Step-by-step explanation:

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Hiiiii, the answer is (x,-y)

Step-by-step explanation:

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2 years ago

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2%7D%20%5Cfrac%7B7%7D%7B8%7D" id="TexFormula1" title="\sqrt{2} \frac{7}{8}" alt="\sq

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2 years ago

2 of 8 = Given that y = 10 cm and 0 = 19°, work out x rounded to 1 DP. у х oo

Drupady [299]

Answer:

x = 3.255 cm

Step-by-step explanation:

Given:

⇒ y = 10cm

⇒ θ = 19

To find:

⇒ Value of "n"

Solution

⇒ By Pythagoras theorem

⇒ Δ Sin θ = n/y

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⇒ n = 0.3255 × 10

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2 years ago

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

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2 years ago

Find the loss or gain % when 20 pens are sold for the CP of 25 pen.

mel-nik [20]

Answer:

20% gained

Step-by-step explanation:

25 - 20 = 5

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2 years ago