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hram777 [196]
3 years ago
6

Clare says’ this classroom is 11 m long in metres longer than a year so if I measure the length of the classroom I will get less

than 11 yards .do u agree with Clare
Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

No I don't agree with Clare.

You will get more than 11 yards

Step-by-step explanation:

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Can anyone help me solve ...​
DochEvi [55]

Answer:

a)    x= 34°

b)    x = 51°

Step-by-step explanation:

Points to keep in mind when solving  triangle problems.

An isosceles triangle has two equal sides and the angles opposite to those sides are also equal angles.

A triangle with all sides equal is called an equilateral triangle, which is also called equiangular triangle.  

8 0
3 years ago
Mr Dominguez spends three weeks training for a marathon. Every day he runs 1/2 mile more than the day before. If the first day h
barxatty [35]
Answer: 16 miles


Explanation:
I believe it would be 16 miles, if he starts off at 6 miles on day one and goes up 1/2 mile every day, he would be up a mile every other day, basically on day 3 he would be at 7 and day 5 at 8 miles, if the pattern continues he would be at 16 miles by day 21.
3 0
3 years ago
Which shapes have parallel sides
guajiro [1.7K]

Answer:

All parallelograms have at least 1 parallel side.(Rectangles,squares,rhombuses,etc.)Trapezoids also have parallel sides.

Step-by-step explanation:

3 0
3 years ago
How to multiply a whole number and a mixed fraction?
Ugo [173]
Convert the mixed number into a decimal and multiply on a calculator (or by hand).
4 0
3 years ago
A1,a2,a3....a30-each of these 30 sets has 5 elements.b1,b2,....bn-each of these n sets has 3 elements.union of a1,a2...a30=union
zzz [600]
 the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x.  Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set.  if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times.  This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
5 0
3 years ago
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