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vampirchik [111]
3 years ago
7

Determine if biconditional is true. A) Felipe is a swimmer if and only if he is an athlete.

Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0
It is not a true biconditional.
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What is the reciprocal of 100
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Answer:

0.01

Steps:

The definition of "reciprocal" is simple. To find the reciprocal of any number, just calculate "1 ÷ (that number)." For a fraction, the reciprocal is just a different fraction, with the numbers "flipped" upside down (inverted). For instance, the reciprocal of 3/4 is 4/3

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Use the elimination method to solve the system of equations. Choose the correct ordered pair.
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You answer is A. You have to substitute the values of x and y into the equation.

(3*1)= 4-1
 
4-(2*1)=2

(4,1)
(x,y)
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A nationwide survey of 1000 adults found that 50​% of respondents favored a plan to break up the 12​ megabanks, which then contr
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a. The population for the study is a total of 1000 adults, so the 50% that favored the plan made up a total of 500 people, since 500 is 1/2 (or 50%) of 1000.

b. The percentage provided is an inferential statistic. Inferential statistics are made by taking a sample of a population and using that sample as data used to make inferences/predictions. Since the percentage provided is a sample of a population being used to make a prediction, it is an inferential statistic.

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3 years ago
Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.
Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

<u>Step 1</u>

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

<u>Step 2</u>

Using the distance formula

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given E(-2,3), F(1,6)

|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given F(1,6), G(4,3)

|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}

Given G(4,3), H(1,0)

|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}

Given E (−2, 3), H (1, 0)

|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}

<u>Step 3</u>

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|=\frac{6-3}{1+2} =\frac{3}{3}=1

Segment GH, G (4, 3), H (1, 0)

Slope of |GH|= \frac{0-3}{1-4} =\frac{-3}{-3}=1

<u>Step 4</u>

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH|= \frac{0-3}{1+2} =\frac{-3}{3}=-1

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| =\frac{3-6}{4-1} =\frac{-3}{3}=-1

<u>Step 5</u>

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

<u>Step 6</u>

<u>Segment EF, segment FG, segment GH, and segment EH are congruent. </u>

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

<u>Step 7</u>

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

4 0
3 years ago
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Plzzzzz teach this.....<br>I wiil Mark as brainlist answer if correct​
GuDViN [60]
Omg don’t open that file it’s takes all your information
7 0
2 years ago
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