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3 years ago

Determine if biconditional is true. A) Felipe is a swimmer if and only if he is an athlete.

Mathematics

1 answer:

Fynjy0 [20]3 years ago

6 0

It is not a true biconditional.

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a farmer has a rectangular field that measures 125 feet by 200 feet. He wants to enclose the field with a fence. What is the tot

grandymaker [24]

He needs to fence the entire perimeter, so all you have to do is find the perimeter. P= S+S+S+S, which is 125, 200, 125, and 200. Add them together and you get 650, so he needs 650 feet of fence.

4 0

3 years ago

A field has a length of 6 2/3 yards and a width of 4 3/4 yards. What is the area of the field.

gulaghasi [49]

Answer:

Ste-by-step explanation:

That doesn’t answer it stupid

6 0

3 years ago

Share £480 in the ratio 2:3:7

aleksandr82 [10.1K]

£480

2:3:7 = 2+3+7 = 12

2
--- 0f £480 = £80
12

3
--- of £480 = £120
12

7
--- of £480 = £280
12

answer = £80 : £120 : £280

5 0

3 years ago

За – 6а + 2 = 8а + 20 – 5а

Luda [366]

Answer:

a = -3

Step-by-step explanation:

3a - 6a + 2 = 8a + 20 - 5a

Combine Like Terms

-3a + 2 = 3a + 20

-2 -2

-------------------------------------

-3a = 3a + 18

-3a -3a

-------------------------------------

-6a = 18

---- ----

-6 -6

a = -3

4 0

3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago