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Thepotemich [5.8K]
2 years ago
12

2)A chef made 30 donuts in 60 minutes. How long would it take him to make 90 donuts?

Mathematics
2 answers:
vesna_86 [32]2 years ago
3 0

Answer to donut question

the chef can make 45 donuts in 90 minutes

Step-by-step explanation:

30 ÷ 60= 0.5

0.5 × 90= 45

Dimas [21]2 years ago
3 0
Answer for #2 : 3 hours
explanation: 30 donuts = 1 hr
90 donuts = 3 hrs

Answer for #3 : 20 gallons
Explanation: 4 bottles = 8 gallons
Ten bottles = 20 gallons

Answer for #4 : 3 hrs
Explanation: 10 hrs = 30 miles
30 divided by 10 = 3.
3 times 3 is 9.

Answer for #5 : 120 pounds
Explanation: 45 divided by 15 = 3
3 times 40 = 120.

Answer for #6 : $30
Explanation: 6 cans = $12
6 times 2 is 12 = $ 24
3 cans = $6
$24 + $6 = $30

( Trust me. i already took this class)
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Please help me on this problem
Anna71 [15]

Answer:

The pairs of integer having two real solution forax^{2} -6x+c = 0 are

  1. a = -4, c = 5
  2. a = 1, c = 6
  3. a = 2, c = 3
  4. a = 3, c = 3

Step-by-step explanation:

Given

ax^{2} -6x+c = 0

Now we will solve the equation by putting all the 6 pairs so we get the  following

-3x^{2} -6x-5 = 0 for a = -3 , c=-5

-4x^{2} -6x+5 = 0 for a = -4 , c=5

1x^{2} -6x+6 = 0 for a = 1 , c=6

2x^{2} -6x+3 = 0 for a = 2 , c=3

3x^{2} -6x+3 = 0 for a = 3 , c=3

5x^{2} -6x+4 = 0 for a = 5 , c=4

The above  all are Quadratic equations inn general form ax^{2} +bx+c=0

where we have a,b and c constant values

So for a real Solution we must have

Disciminant , b^{2} -4\timesa\timesc \geq 0

for a = -3 , c=-5 we have

Discriminant =-24 which is less than 0 ∴ not a real solution.

for a = -4 , c=5 we have

Discriminant = 116 which is greater than 0 ∴ a real solution.

for a = 1 , c=6 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 2 , c=3 we have

Discriminant =12 which is greater than 0 ∴ a real solution.

for a = 3 , c=3 we have

Discriminant =0 which is equal to 0 ∴ a real solution.

for a = 5 , c=4 we have

Discriminant =-44 which is less than 0 ∴ not a real solution.

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Answer:

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lnx=log_{e}x\\\\f(x) = ln({\frac{x^{2}}{4}})\Rightarrow f(x)=ln{x^2}-ln4\Rightarrow f(x)=2lnx-ln4\\g(x) = 2 ln x - ln 4

2) Check the graph below to see this equivalence. to see x>0 they  both coincide.

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