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3 years ago

What digit is missing from the quotient?

Mathematics

2 answers:

finlep [7]3 years ago

6 0

Answer:

1 is missing

Step-by-step explanation:

As 4285 ÷ 7 = Quotient- 612 , Remainder - 1

hodyreva [135]3 years ago

4 0

Answer:

Step-by-step explanation:

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In a game of poker a hand of five cards is dealt to each player from a deck of 52 cards. find the probablility of a hand contain

aalyn [17]

Answer:

0.00597

Step-by-step explanation:

Given,

Total number of cards = 52,

In which flush cards = 20,

Also, the number of spade flush cards = 5,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Thus, the probability of a hand containing a spade flush, if each player has 5 cards

$=\frac{\text{Ways of selecting a spade flush card}}{\text{Total ways of selecting five cards}}$

$=\frac{^{20}C_5}{^{52}C_5}$

$=\frac{\frac{20!}{5!15!}}{\frac{52!}{5!47!}}$

$=\frac{15504}{2598960}$

= 0.00597

7 0

3 years ago

A group of children 6 to 10 years old were asked how many video games they owned. The scatter plot shows the results. What is th

jolli1 [7]

The range of the video games owned for the cluster is between 8 to 10.

Given

A group of children 6 to 10 years old were asked how many video games they owned.

The scatter plot shows the results.

<h3>What is the range?</h3>

The range is the difference between the lowest and highest numbers in a data set.

The range of video games owned for the cluster is 8 to 10.

Therefore,

The range of the video games owned for the cluster is;

$\rm Range = Highest \ value - lowest \ value\\\\Range=10-8\\\\Range=2$

Hence, the range of the video games owned for the cluster is between 8 to 10.

To know more about Range click the link given below.

brainly.com/question/8041076

7 0

3 years ago

A traffic helicopter descends 153 meters to be 445 meters above the ground, as illustrated in the

sertanlavr [38]

Answer:

598 meters

Step-by-step explanation:

In the problem, the word 'decend' means to decrease in elevation.

Our equation:

$? - 153 = 445$

Add 153 to both sides of the equation:

$?= 598$

598 meters represents the original height of the helicopter.

6 0

2 years ago

A translation by_____ units to the right/left and _____ units up down

Alexandra [31]

8 units left and 5 units up

8 0

3 years ago

Read 2 more answers

Let X1,X2......X7 denote a random sample from a population having mean μ and variance σ. Consider the following estimators of μ:

Viefleur [7K]

Answer:

a) In order to check if an estimator is unbiased we need to check this condition:

$E(\theta) = \mu$

And we can find the expected value of each estimator like this:

$E(\theta_1 ) = \frac{1}{7} E(X_1 +X_2 +... +X_7) = \frac{1}{7} [E(X_1) +E(X_2) +....+E(X_7)]= \frac{1}{7} 7\mu= \mu$

So then we conclude that $\theta_1$ is unbiased.

For the second estimator we have this:

$E(\theta_2) = \frac{1}{2} [2E(X_1) -E(X_3) +E(X_5)]=\frac{1}{2} [2\mu -\mu +\mu] = \frac{1}{2} [2\mu]= \mu$

And then we conclude that $\theta_2$ is unbiaed too.

b) For this case first we need to find the variance of each estimator:

$Var(\theta_1) = \frac{1}{49} (Var(X_1) +...+Var(X_7))= \frac{1}{49} (7\sigma^2) = \frac{\sigma^2}{7}$

And for the second estimator we have this:

$Var(\theta_2) = \frac{1}{4} (4\sigma^2 -\sigma^2 +\sigma^2)= \frac{1}{4} (4\sigma^2)= \sigma^2$

And the relative efficiency is given by:

$RE= \frac{Var(\theta_1)}{Var(\theta_2)}=\frac{\frac{\sigma^2}{7}}{\sigma^2}= \frac{1}{7}$

Step-by-step explanation:

For this case we assume that we have a random sample given by: $X_1, X_2,....,X_7$ and each $X_i \sim N (\mu, \sigma)$

Part a

In order to check if an estimator is unbiased we need to check this condition:

$E(\theta) = \mu$

And we can find the expected value of each estimator like this:

$E(\theta_1 ) = \frac{1}{7} E(X_1 +X_2 +... +X_7) = \frac{1}{7} [E(X_1) +E(X_2) +....+E(X_7)]= \frac{1}{7} 7\mu= \mu$

So then we conclude that $\theta_1$ is unbiased.

For the second estimator we have this:

$E(\theta_2) = \frac{1}{2} [2E(X_1) -E(X_3) +E(X_5)]=\frac{1}{2} [2\mu -\mu +\mu] = \frac{1}{2} [2\mu]= \mu$

And then we conclude that $\theta_2$ is unbiaed too.

Part b

For this case first we need to find the variance of each estimator:

$Var(\theta_1) = \frac{1}{49} (Var(X_1) +...+Var(X_7))= \frac{1}{49} (7\sigma^2) = \frac{\sigma^2}{7}$

And for the second estimator we have this:

$Var(\theta_2) = \frac{1}{4} (4\sigma^2 -\sigma^2 +\sigma^2)= \frac{1}{4} (4\sigma^2)= \sigma^2$

And the relative efficiency is given by:

$RE= \frac{Var(\theta_1)}{Var(\theta_2)}=\frac{\frac{\sigma^2}{7}}{\sigma^2}= \frac{1}{7}$

5 0

3 years ago