Answer:A=32.13 cm²
P=23.88cm
Step-by-step explanation:
A consists from arae of Δ ABA and area half circle (Ahc)
AB=a=R=6cm
At=a²/2= 6²/2=36/2=18 cm²
Ahc=r²π/2=3²π/2= 9/2π=4.5πcm²=14.3cm²
A=At+Ahc=18+4.5π=4.5(4+π)cm²=32.13cm²
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a=6cm
d=AC
d=a√2
d=6√2cm
Phc--P of half circle
P = Phc+a+d
Phc=2rπ/2
Phc=rπ
Phc=3πcm
P=3π+6+6√2
P=9.42+6+8.46
P=23.88cm²
Answer:
7.62
Step-by-step explanation:
We can use the distance formula
d = sqrt( (x2-x1)^2 + ( y2- y1) ^2 )
d = sqrt( (1 - -2)^2 + ( 4 - -3) ^2 )
d = sqrt( (1 +2)^2 + ( 4 +3) ^2 )
d = sqrt( (3)^2 + ( 7) ^2 )
d = sqrt( 9+49)
d = sqrt( 58)
7.615773106 or approximately 7.62
The 2s are in the hundreds and tens place
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