Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
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9/18 in lowest term is 1/2
Work:
9/18 ÷ 9/9 = 1/2
1/2 = 0.5
0.5 = 50%
Answer:
39%
Step-by-step explanation:
Answer:
89
Step-by-step explanation:
= √ 64 +9²
=8 +81
=89
Answer:
If there are 324 paving stones, it will cost $1539
Step-by-step explanation:
324 x 4.75 = 1539
