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umka21 [38]
3 years ago
7

Solve the equation I= prt for t A- t= ipr B- t=I/pr C- t= pr/I

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0
The answer is B. t = I/pr
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Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig
Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3466, \sigma = 546

If we randomly select a baby, what is the probability that it has a low birth weight?

This is the pvalue of Z when X = 2500. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2500 - 3466}{546}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384

3.84% probability that it has a low birth weight

3 0
3 years ago
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tino4ka555 [31]

Step-by-step explanation:

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3 years ago
Here is a growing pattern of squares:
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Answer:

squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1

Step-by-step explanation:

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Which letter is it?​
Natali [406]

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Step-by-step explanation:

5 0
3 years ago
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Find the prime facrorization for 100 A.2² × 5² B.2×50 C.4×25 D.2³ × 5² E. 2² × 5³ ​
d1i1m1o1n [39]

Answer:

A

Step-by-step explanation:

100-25*4=5 squared*2 sqaured

so A

6 0
3 years ago
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