Answer:
<em>addpath C:\Program Files\MATLAB\ToolBoxes-20181106T221851Z-001\ToolBoxes\SPM\spm12</em>
<em>savepath</em>
Explanation:
The error clearly indicates that the SPM is missing and is not properly installed. In order to correct this, the following commands are required to be run in the command line of the MATLAB.
These commands will do following.
The first command is the addpath, this will add the path of the toolboxes in the working directory path of the MATLAB
<em>addpath C:\Program Files\MATLAB\ToolBoxes-20181106T221851Z-001\ToolBoxes\SPM\spm12</em>
The second command is the savepath, this will save the additional added path of the working directory for future use.
<em>savepath</em>
Answer:
Well, the answer is simple. Everybody!
Explanation:
Answer:
The main circuit board of a computer is the Motherboard. The Processor(CPU) is located on the circuit board. The Processor(CPU) is the circuitry that processes information. The CPU is also known as the brain of the computer. The speed of the processor is controlled by the clock. The system clock controls the timing of all computer operations.
Explanation:
Answer:
<em>The registers that are compared are instructions 3 and 4</em>
<em>Explanation:</em>
<em>From the question given,</em>
<em>Recall that we need to explain what the hazard detection unit is doing during the 5th cycle of execution and which registers are being compared.</em>
<em>Now,</em>
<em>The instructions on the 5th cycle, at the stage ID/EX and IF/ID:</em>
<em>The instruction values are in ID/EX : sub $t2, $t3, $t6 (instruction 3)</em>
<em>The instruction values are in IF/ID: sub $t3, $t1 $t5 (instruction 4)</em>
<em>The register $t3 is compared in the instructions 3 and 4</em>
<em>The hazard detection unit between instruction 4 and 5t o be compared, it need to find out the values of $t1</em>
<em />
The logical expressions are
- (X NOR Y ) OR Z ⇒
- (A NAND B) AND NOT C ⇒
<h3>How to determine the
logical expressions?</h3>
<u>Logical expression 1</u>
X and Y are linked by the NOR gate.
So, we have:
X NOR Y
The X NOR Y is linked to Z by the OR gate.
So, we have:
(X NOR Y) OR Z
Hence, the logical expression is (X NOR Y ) OR Z ⇒
<u>Logical expression 2</u>
A and B are linked by the NAND gate.
So, we have:
A NAND B
The A NAND B is linked to C by the AND gate.
So, we have:
(A NAND B) AND C
Hence, the logical expression is (A NAND B) AND NOT C ⇒
See attachment for the truth tables
Read more about truth tables at:
brainly.com/question/27989881
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