I’m not sure about USD but Canadian dollars are greater, one dollar CAD is equal to $0.79 US. So $10 CAD is equal to $7.90 US.
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
Answer:
Explanation:
This program is written in Python. It is a function that takes in two arrays. Then it loops through the first array twice, adding each element with the others and comparing the sum to the values in the second array. If a similar value is found in the second array, the program prints out the value and returns True to the user. Otherwise, it returns False. A test case has been created with two array variables that print out False, the output can be seen in the attached image below.
def sumArray(arr1, arr2):
for i in range(len(arr1)):
for x in range(len(arr1)):
sum = 0
if i != x:
sum = arr1[i] + arr1[x]
if sum in arr2:
print(str(sum) + "Found in Second Array")
return True
return False
arr1 = [1, 9, 10, 44]
arr2 = [2, 4, 8, 14]
print(sumArray(arr1, arr2))