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2 years ago

SELECT THE BEST ANSWER

Mathematics

1 answer:

bearhunter [10]2 years ago

8 0

Answer:

3a² + 13ab - 10b²

Step-by-step explanation:

(3a - 2b)(a + 5b)

Each term in each bracket multiplies each term in the other bracket.

3a(a + 5b) -2b(a + 5b)

3a² + 15ab - 2ab - 10b²

3a² + 13ab - 10b²

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I need help on this.. First person to answer this correctly gets a BRANLIST

arlik [135]

Answer: The relation is a function.

Step-by-step explanation: Since there is one value of y for every value of x in (-2,4), (3,7), (0,8), (5,8), and (1,6), this relation is a function.

I hope this helps you out!

7 0

2 years ago

Which expression has a value of 15 when n = 7? 43 minus 5 n 3 n minus 5 6 n minus 28 19 minus StartFraction 28 Over n EndFractio

andrey2020 [161]

Answer:

$19-\dfrac{28}{n}$ is the expression with value of 15 when n = 7.

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

$43-5n$

Substituting the value of n,

$43-5\left(7\right)$

Simplifying,

$43-35=8$

Since the value of the expression is 8 which is not equal 15.

Hence expression $43-5n$ does not have value of 15 when n = 7.

Expression 2:

$3n-5$

Substituting the value of n,

$3\left(7\right)-5$

Simplifying,

$21-5=16$

Since the value of the expression is 16 which is not equal 15.

Hence expression $3n-5$ does not have value of 15 when n = 7.

Expression 3:

$6n-28$

Substituting the value of n,

$6\left(7\right)-28$

Simplifying,

$42-28=14$

Since the value of the expression is 14 which is not equal 15.

Hence expression $6n-28$ does not have value of 15 when n = 7.

Expression 4:

$19-\dfrac{28}{n}$

Substituting the value of n,

$19-\dfrac{28}{7}$

Simplifying,

$19-4=15$

Since the value of the expression is 15 which is equal 15.

Hence expression $19-\dfrac{28}{n}$ has the value of 15 when n = 7.

4 0

3 years ago

Read 2 more answers

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

$P(X \ge 1) = 0.509$

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$

Here n = 6

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{1 * 12376}{38760}]$

$P(X \ge 1) =1- 0.3193$

$P(X \ge 1) = 0.6807$

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3 years ago

Which illustrates the construction of a perpendicular to a line from a point on the line?

quester [9]

I believe the correct answer from the choices listed above is the last option. The last option clearly describes the illustration of the construction of a perpendicular to a line from a point on the line where you start on a point in the line. Using an arbitrary radius, draw arcs intersecting the line <span> at two points. </span>
Hope this answers the question. Have a nice day.

6 0

2 years ago

Read 2 more answers

The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a

xeze [42]

Answer:

what does this mean you just put random numbers right?

Step-by-step explanation:

3 0

2 years ago