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2 years ago

What is the sum of (x ^ 2 - 3x + 2) and (5x ^ 2 - 3x - 8)

Mathematics

1 answer:

geniusboy [140]2 years ago

5 0

Answer:

6x^2-6x-6

Step-by-step explanation:

(x^2-3x+2)+(5x^2-3x-8)

x^2+5x^2-3x+(-3x)+2+(-8)

6x^2-3x-3x+2-8

6x^2-6x+2-8

6x^2-6x-6

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What is the inverse of Y=-5x-7

Pepsi [2]

Answer:y = - 5x - 7

Step-by-step explanation:The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

here m = - 5 and b = - 7, hence

y = - 5x - 7 ← equation of line

7 0

3 years ago

Can you help me on this question Plss??

prohojiy [21]

Linear and consistent

6 0

2 years ago

Make an equation for the line v=(6,6) is perpendicular to y=-2/3x-11

natali 33 [55]

Answer:

y=-2/3x+10

Step-by-step explanation:

y=2/3x-11

plug in plot and remove intercept

6=-2/3(6)+b

6=-4+b

10=b

y=-2/3x+10

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2 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

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1 year ago

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pychu [463]

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3 years ago