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3 years ago

Please I need it tomorrow

Mathematics

2 answers:

pashok25 [27]3 years ago

8 0

Answer: (a) 11

Step by step

= 4 + 10 – 3

= 14 – 3

= 11

Answer : (b) 8

Step by step

= 4 + 2 ( 5 −3)

= 4 + 4

= 8

Ainat [17]3 years ago

4 0

Answer:

a is 11

Step-by-step explanation:

4+2(5)+-3 is ll

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What is the solution-|-x|=-12

andreev551 [17]

The solution to the equation includes both the positive and negative portions of the solution. x = 12, -12

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4 years ago

I NEED EXPERT..ILL GIVE BRAINLEST

sashaice [31]

I’m here to help what’s the problem?

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3 years ago

In a basketball game Elena scored twice as many points as Tyler Tyler scores four points fewer than Noah and Noah scores three p

saveliy_v [14]

Full question:

In a basketball game, Elena scores twice as many points as Tyler. Tyler scores four points fewer than Noah, and Noah scores three times as many points as Mai. If Mai scores 5 points, how many points did Elena score? Explain your reasoning

Answer and explanation:

We start from known to unknown. We know that Mai scored 5 points and so we work from here.

Since Mai scored 5 points and Noah scored three times as many points then Noah's score = 3×5= 15 points

Since Tyler scored four points less than Noah, Noah's score= 15-4= 11 points

Finally Elena's score is twice that of Tyler hence Elena's score =2×11= 22 points

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3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

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3 years ago

Will give Brainliest

Vedmedyk [2.9K]

I hope you will get it

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3 years ago