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Lady bird [3.3K]
3 years ago
5

In a chest there are some gold coins. Captain takes half the

Mathematics
2 answers:
Julli [10]3 years ago
5 0

Answer:

There were 12 gold coins in the chest at the start.

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

x = Number of gold coins in a chest

1/2x = Number of gold coins taken by the captain

1/4x = Number of gold coins taken by Sally

3 = Number of gold coins left

2. How many coins were in the chest at the start?

Let's write the following equation to solve for x:

1/2x + 1/4x + 3 = x

2x + x + 12 = 4x (Lowest Common Denominator is 4)

4x - 2x - x = 12 (Like terms)

x = 12

There were 12 gold coins in the chest at the start.

Hope this helps :D

Alina [70]3 years ago
3 0

Answer:

7

Step-by-step explanation:

4+3=7

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5x - 6 = -16 (Show work)
zysi [14]
  • <em>Answer:</em>

<em>x = - 2</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>5x - 6 = - 16</em>

<em>5x = - 16 + 6</em>

<em>5x = - ( 16 - 6)</em>

<em>5x = - 10</em>

<em>x = - 10 : 2</em>

<em>x = - 2</em>

<em>Good luck ! </em>

6 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Choose the graph that represents the following system of inequalities: y ≤ −3x + 1 y ≤ 1 over 2x + 3 In each graph, the area for
Vanyuwa [196]

The graph that represents the inequality has been shown in the attachment.

<h3>How to solve for the graph</h3>

We have these equations

y ≤ −3x + 1

y ≤ x + 3

We remove the inequality sign from both of these equations

y = −3x + 1

y = x + 3

−3x + 1  = x + 3

such that

x = -0.5

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x + 3 = -0.5 + 3

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we test for the origin. 0,0

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for  x + 3

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This is 0≤1 and 0≤3

Hence the graph should be shaded to the origin.

Read more on a graph here: brainly.com/question/14030149

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Answer:

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3 years ago
Which of the following equations represents a quadratic relation?
iVinArrow [24]

Answer:

y=2x^2+1

Step-by-step explanation:

a quadratic equation has a x^2 term

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