Answer:
120 ways
Step-by-step explanation:
Alice, Bob, David, Charlie, Eve
David, Alice, Bob, Charlie, Eve
Alice,David, Bob, Charlie, Eve
Charlie, Eve ,Alice,David, Bob,
Charlie, Eve ,Alice, Bob, David,
Charlie, Eve ,David, Alice, Bob,
Alice,Charlie, Eve , Bob, David,
Alice,Charlie, Eve , David, Bob,
Bob,Alice,Charlie, Eve , David, and so .
This is a permutation question as the order of placing Charlie to the left of Eve is important.
So the total number of people n= 5 and the possible order is 4 keeping Charlie left of Eve. Eve cannot have the last position to keep Charlie on the left.
Using the formula of nPr = n!/ (n-r)! we get
5! / (5-4)! = 120 ways in which Charlie can be placed to the left of Eve.
