Question

Find the following algebra, I am in class and plz give explanation

Answer 1

1) Solving $4a+4b-ac-bc$ we get $(a+b)(4-c)$

2) Solving $16a^4-8b$ we get $8(2a^4-b)$

3) Solving $x^2-8x+15$ we get $(x-3)(x-5)$

Step-by-step explanation:

We need to solve the following expressions:

1) $4a+4b-ac-bc$

We will solve this expression by factoring common terms:

$4a+4b-ac-bc$

Factoring 4 from 4a+4b and -c from -ac-bc

$4(a+b)-c(a+b)$

Taking common term

$(a+b)(4-c)$

2) $16a^4-8b$

We will solve this expression by factoring common terms:

$16a^4-8b$

Taking 8 as common term:

$8(2a^4-b)$

3) $x^2-8x+15$

We can solve the expression by breaking the middle term into 2

$x^2-3x-5x+15\\Finding\,\,common:\\=x(x-3)-5(x-3)\\=(x-3)(x-5)$

Keywords: Finding factors

Learn more about Finding factors at:

• brainly.com/question/10771256
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