Recall: The Exterior Angle Theorem of a Triangle states that the size of the exterior angle of a triangle equals the sum of the two sizes of the two opposite angles of the triangle.
a. Based on the theorem,
Q° = 41° + 54° = 95°
b.
✔️122° = 4a + 2a (exterior angle theorem)
122 = 6a
Divide both sides by 6
122/6 = a
a = 20.3
✔️122° + 3b = 180° (angles on a straight line)
3b = 180 - 122
3b = 58
b = 58/3
b = 19.3
Question 2:
Recall: Opposite angles of a parallelogram are equal while adjacent/consecutive angles are supplementary.
