Find the linearization Upper L (x comma y )of the function f (x comma y )at Upper P 0. Then find an upper bound for the magnitud
e StartAbsoluteValue Upper E EndAbsoluteValue of the error in the approximation f (x comma y )almost equalsUpper L (x comma y )over the rectangle R. f (x comma y )equals3 ln x plus 5 ln y at Upper P 0 (1 comma 1 )R: StartAbsoluteValue x minus 1 EndAbsoluteValue less than or equals 0.4, StartAbsoluteValue y minus 1 EndAbsoluteValue less than or equals 0.3
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Dana can type 90 words per minute.
Since, 1 minute = hours
Therefore, number of words she can type =
= 90×60
= 5400 words per hour
If she types words in 'x' hours.
Number of words Dana types with the given speed in 'x' hours = Speed of typing × Time
=
Therefore,
hours
Therefore, Dana types words in 48.15 hours.
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