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ipn [44]
3 years ago
10

Find the linearization Upper L (x comma y )of the function f (x comma y )at Upper P 0. Then find an upper bound for the magnitud

e StartAbsoluteValue Upper E EndAbsoluteValue of the error in the approximation f (x comma y )almost equalsUpper L (x comma y )over the rectangle R. f (x comma y )equals3 ln x plus 5 ln y at Upper P 0 (1 comma 1 )​R: StartAbsoluteValue x minus 1 EndAbsoluteValue less than or equals 0.4​, StartAbsoluteValue y minus 1 EndAbsoluteValue less than or equals 0.3

Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

I E I ≤ 0.0522

Step-by-step explanation:

See attached image file

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<h2>Answer:</h2>

The rate of change between the points (–3, 0) and (–2, –5) is:

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<h2>Step-by-step explanation:</h2>

The rate of change between the points (-5, 10) and (-4, 5) is -5.

Now we are asked to find the average rate of change between (-3,0) and (-2,-5)

We know that the average rate of change between two points (a,b) and (c,d) is calculated by the formula:

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Here we have:

(a,b)=(-3,0) and (c,d)=(-2,-5)

Hence, the average rate of change is:

 Rate\ of\ change=\dfrac{-5-0}{-2-(-3)}\\\\\\Rate\ of\ change=\dfrac{-5}{-2+3}\\\\\\Rate\ of\ change=-5

Also, we know that for any linear function the average rate of change is same between any two points.

           Hence, the answer is:

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8 0
3 years ago
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Answer question from picture.
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