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Sonja [21]
2 years ago
13

Please answer illgive BRAINLIEST

Mathematics
1 answer:
Aleks04 [339]2 years ago
8 0

Answer:

It's B. 31.79in²

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Nataliya [291]
It's saying that B is equal to 1, and c is equal to 4. So your gonna square B (multiply it by itself) and add c. Make sense?
6 0
3 years ago
How would you solve this
nika2105 [10]
To find 10% you would just divide 200 by 10
=200/10
=20

hope this helped !
3 0
3 years ago
A local grocery story has strawberries on sale for $1.45 per pound. How much would it cost to buy 5.5 pounds of strawberries? Ro
myrzilka [38]

Answer: The cost of 5.5 pounds strawberries =$ 7.98

Step-by-step explanation:

Given: A local grocery story has strawberries on sale for $1.45 per pound.

i.e. Cost for 1 pound strawberries = $1.45

Now, Cost of 5.5 pounds strawberries =  5.5 x (Cost for 1 pound strawberries)

= $ (5.5 x  1.45)

= $ 7.975 ≈ $ 7.98   [ Round to the nearest penny]

Hence, the cost of 5.5 pounds strawberries =$ 7.98

5 0
3 years ago
*PLEASE HURRY WILL GIVE BRAINLY* A company's profits (in dollars) are modeled by the function p(x) = —x^2+ 1100x - 300000, where
LekaFEV [45]
No, it’s not correct. The y-axis on the graph represents the profits p(x) so the minimum number of units produced should be when the a horizontal line at y = 590 first intersects the parabola drawn left to right, and not a vertical line at x = 590 because that represents the profit as 590 units are produced.
4 0
3 years ago
Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
3 years ago
Read 2 more answers
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